5CV006 Alternative Assessment 2 (-) Firs
以下为《5CV006 Alternative Assessment 2 (-) Firs》的无排版文字预览，完整内容请下载
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Faculty of Science and Engineering
School of Architecture and the Built Environment
Assessment Brief
Module
5CV006 LAND SURVEYING
Module Leader
Dr. Georgios Papavasileiou
Semester
3
Year
2020-21
Assessment Number
2
% of module mark
50
Due Date
To be communicated by the local tutor
Hand-in – what?
Electronic submission.
Hand-in- where?
Submission by email to G.Papavasileiou@wlv.ac.uk
Pass mark
40%
Feedback
To be communicated by email
Collection of marked work
To be communicated by email
Learning outcomes:
LO1 Understanding of and ability to use relevant materials, equipment, tools, processes, or products
LO2 Awareness of team roles and the ability to work as a member of an engineering team.
LO3 Underpinning science and maths.
ASSIGNMENT BRIEF
This assignment intends to assess your understanding of the procedures and practices related to the surveying methods and techniques outlined in this module. This is an alternative to the final exam which has been revised from a closed-book time-restricted exam under supervised conditions to an electronic portfolio submission.
Part 1 – Traditional methods
Scenario:
You have conducted a survey for the construction of a new road and collected the following information:
Point
Distance
(m)
Foresight
(m)
Backsight
(m)
QB
A
Ν/Α
Ν/Α
Ν/Α
N 4° 9' 0.56'' E
B
252.285
3.7215
2.429
S 70° 11' 13.5'' E
C
276.471
3.6015
2.446
N 75° 22' 52.18'' E
D
233.033
3.8265
2.037
N 15° 14' 14.31'' E
E
310.135
3.9675
2.361
N 19° 37' 49.72'' E
F
164.447
3.378
1.814
N 80° 44' 41.9'' E
G
141.133
3.2145
2.168
S 59° 48' 35.26'' E
H
261.375
4.4145
2.087
N 45° 19' 20.16'' E
I
332.649
3.6915
2.058
N 73° 24' 26.28'' E
J
106.208
4.011
2.219
N 14° 42' 4.4'' E
K
126.248
3.7935
2.136
N 17° 13' 58.42'' E
L
136.132
3.57
2.696
S 52° 42' 58.17'' W
The altitude at point A is 10m. Assume that point A is the datum. All the above measurements were done sequentially.
Prepare a table using the theoretical approaches taught in this module which contains the following information:
Point coordinates
Departures and latitudes
Whole-circle bearings
Vertical angles
Height difference between points and from point A
Actual altitudes
ATTENTION: For this question you need to show your working. Numbers in the table without justification will not receive any marks. The working can be either typed or handwritten (scanned and appropriately introduced to the document), but the table must be editable as the one in this document.
(30 marks)
Point coordinates
Departures
latitudes
Whole-circle bearings
Vertical angles
Height difference between points and from point A
Actual altitudes
A
10,0
0
0
4° 9' 0.56''
0
10
B
-69.373, 236.1039
-79.372
237.400
109° 48' 46.5''
0.654
1.2961
8.7039
C
0.298,234.9684
69.671
267.624
75° 22' 52.18''
-8.745
2.4316
7.5684
D
267.09, 233.1789
266.794
61.289
15° 14' 14.31''
0.545
4.2221
5.7789
E
559.237, 231.5725
292.147
104.205
19° 37' 49.72''
-0.923
5.8275
4.1725
F
585.549, 230.0085
26.312
162.309
80° 44' 41.9''
0.856
7.3915
2.6085
G
514.7,228.962
-70.849
121.939
120° 11' 14.74''
-1.795
8.438
1.562
H
698.447,226.6345
183.747
185.838
45° 19' 20.16''
0.948
9.2345
0.7655
I
793.585,225.001
95.138
318.678
73° 24' 26.28''
-0.891
12.399
-2.399
J
896.288,223.209
102.703
26.977
14° 42' 4.4''
2.225
14.191
-4.191
K
1016.855,221.5515
120.567
37.369
17° 13' 58.42''
-2.152
15.8485
-5.8485
L
934.359,220.6775
-82.496
108.361
127° 17' 1.83''
1.865
16.7225
-6.7225
Quadrant angle: A 4° 9' 0.56'' B 109° 48' 46.5'' C 75° 22' 52.18'' D 15° 14' 14.31''
E 19° 37' 49.72'' F 80° 44' 41.9'' G 120° 11' 14.74'' H 45° 19' 20.16''
I 73° 24' 26.28'' J 14° 42' 4.4'' K 17° 13' 58.42'' L 127° 17' 1.83''
latitudes= Sin x distance
SinA :0.0723 SinB:0.941 SinC:0.968 SinD:0.263 SinE:0.336 SinF:0.987 SinG:0.864 SinH:0.711
SinI:0.958 SinJ:0.254 SinK:0.296 SinL:0.796
Example : 0.968x252.285=237.400
Departures=Cos x distance
CosA:0.997 cosB:-0.339 cosC:0.252 cosD ：0.965 cosE：0.942 cosF：0.160
cosG：-0.502 cosH:0.703 cosI：0.286 cosJ:0.976 cosK:0.955 cosL：-0.606
Example:-0.339x252.285=-79.372
Hb=2.429-3.7215=-1.2961 Hc=2.446-3.6015=-1.1355 Hd=2.037-3.8265=-1.7895
He=2.3611-3.9675=-1.6064 Hf=1.814-3.378=-1.564 Hg=2.168-3.2145=-1.0465
Hh=2.087-4.4145=-2.3275 Hi=2.058-3.6915=-1.6335 Hj=2.219-4.011=-1.792
Hk=2.136-3.7935=-1.6575 Hl=2.696-3.57=-0.874
Y=H + Latitudes
Y1=0 Y2=237.400-1.2961=236.1039 Y3=236.1039-1.1355=234.9684
Y4=234.9684-1.7895=233.1789 Y5=233.1789-1.6064=231.5725
Y6=231.5725-1.564=230.0085 Y7=230.0085-1.0465=228.962
Y8=228.962-2.3275=226.6345 Y9=226.6345-1.6335=225.001
Y10=225.001-1.792=223.209 Y11=223.209-1.6575=221.5515
Y12=221.5515-0.874=220.6775
X=A+ Departurs
Actual altitudes=h(a~l)-H(b~l)
Aa=10 Ab=10-1.2961=8.7039 Ac 8.7039-1.1355=7.5684 Ad=7.5684-1.7895=5.7789
Ae=5.7789-1.6064=4.1725 Af=4.1725-1.564=2.6085 Ag=2.6085-1.0465=1.562
Ah=1.562-2.3275=-0.7655 Ai=-0.7655-1.6335=-2.399 Aj=-2.399-1.792=-4.191
Aj=-4.192-1.6575=-5.8485 Ak=-5.8485-0.874=-6.7225 Al=-6.7225-3.7215=-10.444
Height difference between points and from point A=10-A(b~l)
Example:10-8.7039=1.2961
Vertical angles=tan(-1)*Departure
Draw in scale the above information (including point coordinates, distances, bearings) on a map.
/
(8 marks)
Draw in scale a vertical cut along the line of the survey
(8 marks)
/
What type of traverse is it? Justify your answer.
(4 marks)
Leveling?in?elevation?is?used.?The?basic?principle?of?leveling?is?to?use?the?horizontal?line?of?sight?provided?by?level?to?measure?the?elevation?difference?between?two?points,?so?as?to?calculate?the?elevation?of?unknown?points?with?known?elevations
Part 2 – Modern land surveying
In the following list, modern land surveying equipment currently available in the market is listed. You are required to select two of these.
Modern surveying equipment:
Robotic total station
Self-learning total station
Real-time kinematic (RTK) GPS
Autonomous drone
Microdrones
3D laser scanner
Rotary laser level
For each of the selected pieces of equipment:
Select a commercial model and present it.
Describe its operation.
Provide links to the manufacturer’s website, product website, user manuals, and instructional videos (if available online).
Provide links to two alternative make/models (manufacturer’s website, product website, user manuals, and instructional videos).
Critically assess the strengths and shortcomings of this piece of equipment over traditional ones used for the same operation.
ATTENTION: For this question you need to discuss the operation of the instrument yourselves. Just copying from the user manual will disqualify your whole answer.
ATTENTION: The commercial models you will select cannot be the ones presented in the lectures.
(50 marks)
(Total: 100 marks)
3D laser scanner
3D laser scanner is a breakthrough in surveying and mapping technology. It breaks through the traditional single point measurement method and has the unique advantages of high efficiency and high precision.
Three dimensional has gradually replaced two-dimensional, because its intuitive is two-dimensional can’t express, three-dimensional laser scanner each measurement data contains not only x, y, Z point information, but also R, G, B information, such a comprehensive information can give people a real reappearance of objects in the computer feeling, is the general measurement means can’t do.
3D laser scanner has a wide range of applications, such as surveying and mapping engineering, structural measurement, emergency services, and mining industry can use 3D laser scanner 内容过长，仅展示头部和尾部部分文字预览，全文请查看图片预览。 obtaining an examination paper in advance of its authorised release.
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